Explain stokes law class 11
WebGraham’s law states that the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molar mass. The Formula can be written as. M1 is the molar mass of gas 1. M2 is the molar mass of … WebStoke’s law states that the viscous force acting on a spherical body of radius r moving with velocity v in viscous media of viscosity η is given by, F= – 6πηrv. ... Class 10 Class 12. …
Explain stokes law class 11
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WebNCERT Solutions For Class 11. NCERT Solutions For Class 11 Physics; ... Stoke’s law can explain this. In this article, you will understand Stoke’s law and its derivation in detail. ... Stokes’s law finds application in several areas such as: Settling of sediment in freshwater; WebSep 15, 2024 · Stoke’s Law Formula: When a small spherical body falls in a liquid column with terminal velocity, then viscous force acting on it is. F = 6πηrv. where, r = radius of …
WebSep 21, 2024 · Degrees of Freedom Formula Physics: Suppose if we have A number of gas molecules in the container, then the total number of degrees of freedom is f = 3A. But, if the system has R number of constraints (restrictions in motion) then the degrees of freedom decreases and it is equal to f = 3A-R where A is the number of particles. WebApr 6, 2024 · Archimedes’s principle is extremely important in the study of buoyancy in physics, this principle is explained very briefly in Chapter 10 called mechanical properties of fluids of Class 11 in the NCERT book, this chapter is prescribed by the Central Board of secondary education as it includes various important topics whose understanding is ...
WebAs we know, surface tension is given by the formula, Surface tension = F/L. We know that F = ma, substituting the value in the equation, we get. =ma/L. Equating the fundamental quantities into the equation, we get. … WebApr 6, 2024 · As explained earlier, terminal velocity is attained at an equilibrium position when the net force acting upon the spherical body and acceleration becomes zero. Here …
WebThe law relates to the changes in energy states due to work and heat transfer. ... NCERT Solutions For Class 11. NCERT Solutions For Class 11 Physics; ... the first law fails to explain why heat flows from the hot end …
WebLearn the concepts of Class 11 Physics Mechanical Properties of Fluids with Videos and Stories. Solve Study Textbooks Guides. Join / Login >> Class 11 >> Physics ... Stokes … ox14 1tpWebSolution. Verified by Toppr. The rate of cooling of a body is directly proportional to the difference in temperature of the body and the surrounding. If the temperature of a body. decreases from θ 1 to θ 2 in t seconds, the rate of cooling is, ( tθ 1−θ 2) jeetho hallWebThe law, first set forth by the British scientist Sir George G. Stokes in 1851, is derived by consideration of the forces acting on a particular particle as it sinks through a liquid … ox14 3db to ox10 7nrWebSep 30, 2024 · Stokes’ Law and its formula: Eminent physicist Sir Stokes investigated fluid dynamics and came up with an equation for the viscous drag (F) on a small sphere at low speeds. This formula is now called Stokes’ Law. ox13 5asWebStokes’ Law Shaalaa.com. Maharashtra State Board HSC Science (General) 12th Board Exam. Question Papers 280. Textbook Solutions 13106. MCQ Online Mock Tests 73. Important Solutions 5258. Question Bank Solutions 15292. Concept Notes & Videos 460. Time Tables 26. jeethink webserviceWebJan 17, 2024 · Stokes’s Law. This law gives an expression for the viscous force experienced by a body (a spherical) moving through a fluid. This expression was given by Sir George G. Stokes.When a body falls through a fluid, as shown in Fig. (a), it drags the layer of the fluid in contact with it, and the body experiences a retarding force when there … jeethix tWebApplications: Dynamic lift holds great importance in many fields such as aerodynamics and many ball sports. The dynamic lift is given consideration while designing the rotor ships and aeroplanes. The figure above shows … jeeth tours